Solutions of Triangles

 

Solutions of Triangles

Solutions of Triangles

Solutions of Triangles


Key Concepts:

  • Sine Rule: In any triangle ABC, a/sin A = b/sin B = c/sin C.
  • Cosine Rule: In any triangle ABC, a² = b² + c² - 2bc cos A (and similar formulas for b² and c²).
  • Tangent Rule: tan(A/2) = √[(s-b)(s-c)/(s(s-a))], where s = (a+b+c)/2.
  • Area of a Triangle:
    • Using sides: Δ = √[s(s-a)(s-b)(s-c)] (Heron's formula)
    • Using base and height: Δ = (1/2) * base * height
    • Using two sides and included angle: Δ = (1/2) * ab * sin C

Important Properties:

  • The sum of the angles in a triangle is always 180°.
  • The length of any side of a triangle is less than the sum of the other two sides.
  • In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides (Pythagorean theorem).  

Applications:

  • Solving triangles given various combinations of sides and angles.
  • Finding areas of triangles.
  • Proving trigonometric identities.
  • Solving problems in geometry, physics, and engineering.

Example:

Given a triangle ABC with a = 5, b = 7, and ∠C = 60°, find the remaining sides and angles.

  1. Find angle A: Using the cosine rule, a² = b² + c² - 2bc cos A.

    • 5² = 7² + c² - 27c*cos(60°)
    • 25 = 49 + c² - 7c
    • c² - 7c + 24 = 0
    • (c - 3)(c - 8) = 0
    • So, c = 3 or c = 8. Since c cannot be less than a or b, c = 8.
  2. Find angles B and C: Using the sine rule, a/sin A = b/sin B.

    • 5/sin A = 7/sin B
    • sin B = (7/5) * sin A
    • Using a calculator, we find sin B ≈ 0.9325.
    • So, B ≈ 68.75°.
    • Finally, C = 180° - A - B ≈ 180° - 41.25° - 68.75° = 70°.

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